Asked by Rez
Magnesium metal reacts with hydrochlroic acid according to following reaction:
Mg(s) + 2HCl(aq) -> MgCl2(aq) + H2 (g)
over interval of 10.00s, the mass of Mg changes by -0.22g. What is the corresponding rate of consumption of HCl (in Mol/s) ?
So what i think i should do is first convert the rate of consumption to mol/s and then use that to find corresponding rate of consumption of HCl
This is my work
Molar mass of Mg= 24.3
m=-0.22
n=m/M
n=-0.22/24.3 = -0.009 mol
-0.009 is in 10 seconds so
-0.009/10=-0.0009 mol/s
The ratio between Mg and HCl is 1:2
so
2(-0.0009)=-0.0018 Mol/s
So the rate of consumption of HCl is -0.0018 Mol/s
am i doing anything wrong?
Thanks
Mg(s) + 2HCl(aq) -> MgCl2(aq) + H2 (g)
over interval of 10.00s, the mass of Mg changes by -0.22g. What is the corresponding rate of consumption of HCl (in Mol/s) ?
So what i think i should do is first convert the rate of consumption to mol/s and then use that to find corresponding rate of consumption of HCl
This is my work
Molar mass of Mg= 24.3
m=-0.22
n=m/M
n=-0.22/24.3 = -0.009 mol
-0.009 is in 10 seconds so
-0.009/10=-0.0009 mol/s
The ratio between Mg and HCl is 1:2
so
2(-0.0009)=-0.0018 Mol/s
So the rate of consumption of HCl is -0.0018 Mol/s
am i doing anything wrong?
Thanks
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