Question

-8 squareroot 48 -7 squareroot 27

Answer 1

To simplify the expression \(-8 \sqrt{48} - 7 \sqrt{27}\), we start by simplifying the square roots.

1. **Simplifying \(\sqrt{48}\)**:
\[
\sqrt{48} = \sqrt{16 \times 3} = \sqrt{16} \cdot \sqrt{3} = 4\sqrt{3}
\]
Therefore,
\[
-8 \sqrt{48} = -8 \times 4\sqrt{3} = -32\sqrt{3}
\]

2. **Simplifying \(\sqrt{27}\)**:
\[
\sqrt{27} = \sqrt{9 \times 3} = \sqrt{9} \cdot \sqrt{3} = 3\sqrt{3}
\]
Therefore,
\[
-7 \sqrt{27} = -7 \times 3\sqrt{3} = -21\sqrt{3}
\]

Now we can combine the two simplified terms:
\[
-32\sqrt{3} - 21\sqrt{3} = (-32 - 21)\sqrt{3} = -53\sqrt{3}
\]

Thus, the final result is:
\[
\boxed{-53\sqrt{3}}
\]