Question

squareroot 10 + 6 squareroot 40. simplify.

Answer 1

To simplify the expression \( \sqrt{10} + 6\sqrt{40} \), we start by simplifying \( \sqrt{40} \):

\[
\sqrt{40} = \sqrt{4 \times 10} = \sqrt{4} \times \sqrt{10} = 2\sqrt{10}
\]

Now, substituting \( \sqrt{40} \) into the expression:

\[
\sqrt{10} + 6\sqrt{40} = \sqrt{10} + 6(2\sqrt{10}) = \sqrt{10} + 12\sqrt{10}
\]

Now, we can combine the like terms:

\[
\sqrt{10} + 12\sqrt{10} = (1 + 12)\sqrt{10} = 13\sqrt{10}
\]

Thus, the simplified expression is:

\[
\boxed{13\sqrt{10}}
\]