Question

x^(2)+8x-2=0
A -4+3 squareroot 2
B -8+3 squareroot 2
C 4+3 squareroot 2
D 8+3 squareroot 2

Answer 1

To solve the quadratic equation x^2 + 8x - 2 = 0, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

In this case, a = 1, b = 8, and c = -2. Plugging these values into the quadratic formula:

x = (-8 ± √(8^2 - 4(1)(-2))) / (2(1))
x = (-8 ± √(64 + 8)) / 2
x = (-8 ± √(72)) / 2
x = (-8 ± √(36 * 2)) / 2
x = (-8 ± 6√2) / 2
x = -4 ± 3√2

So the solutions to the quadratic equation are:
x = -4 + 3√2 (option C)
x = -4 - 3√2 (not listed)