Question

-7 squareroot 3 + 4 squareroot 48

Answer 1

To simplify the expression \(-7\sqrt{3} + 4\sqrt{48}\), we first simplify \(\sqrt{48}\).

\[
\sqrt{48} = \sqrt{16 \cdot 3} = \sqrt{16} \cdot \sqrt{3} = 4\sqrt{3}
\]

Now, we substitute \(\sqrt{48}\) back into the original expression:

\[
4\sqrt{48} = 4 \cdot 4\sqrt{3} = 16\sqrt{3}
\]

Now, replace \(4 \sqrt{48}\) in the expression:

\[
-7\sqrt{3} + 16\sqrt{3}
\]

Next, combine the terms by adding the coefficients of \(\sqrt{3}\):

\[
(-7 + 16)\sqrt{3} = 9\sqrt{3}
\]

Thus, the simplified expression is:

\[
\boxed{9\sqrt{3}}
\]