Asked by Shannon
                Solve by the elimination method:
0.3x-0.2y=4
0.4x+0.5y= -29/19 (fraction)??
Please Help I do not understand Algebra!!
            
        0.3x-0.2y=4
0.4x+0.5y= -29/19 (fraction)??
Please Help I do not understand Algebra!!
Answers
                    Answered by
            Ted
            
    to solve this equation by elimination method, you need to make sure that the number in each one of the equation is the same.
you have to pick a no that will fit.
4x0.3x-0.2y=4
3x0.4x+0.5y=-29/19
1.2x-0.8y=16
1.2x+1.5y=87/19
you then cross out the no that is the same and what you have let is:
-0.8y=16
+1.5y=87/19
then you subtract the remaining equation, so it will be:
-0.8y-(+1.5y)=2.3y
16-87/19
the answer you get will be divided by 2.3y and that is how you get the value of y
after you get the value of y, you substitute the value of y into one of the equation that was not multiplied by any no, which is the original equation, then you get the value of x .and yeah that's all. i hope this was helpful
    
you have to pick a no that will fit.
4x0.3x-0.2y=4
3x0.4x+0.5y=-29/19
1.2x-0.8y=16
1.2x+1.5y=87/19
you then cross out the no that is the same and what you have let is:
-0.8y=16
+1.5y=87/19
then you subtract the remaining equation, so it will be:
-0.8y-(+1.5y)=2.3y
16-87/19
the answer you get will be divided by 2.3y and that is how you get the value of y
after you get the value of y, you substitute the value of y into one of the equation that was not multiplied by any no, which is the original equation, then you get the value of x .and yeah that's all. i hope this was helpful
                    Answered by
            Anonymous
            
    4x-8=6
    
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