solve the elimination method for

3x+7y=-32
7x+3y=-8

2 answers

10x+10y=40
dived by 10
x=4
1st times 3 --->9x + 21y = -96
2nd times 7 --> 49x + 21y = -56
subtract them:
40x = 40
x = 1
sub into 1st:
3 + 7y = -32
7y = -35
y = -5

so x = 1 and y = -5