Asked by Willie
A .4 kg ball is attached to a spring with spring constant 12 N/m. If the ball is pulled down .2m from the equilibriu, and released, what is its maximum speed while it oscilates?
Answers
Answered by
drwls
(1/2)kX^2 = (1/2) M Vmax^2
Vmx = X*sqrt(k/m)
X is the maximum amount the spring is stretched (or compressed)
Vmx = X*sqrt(k/m)
X is the maximum amount the spring is stretched (or compressed)
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