Asked by Jayesh
A 0.75-kg ball is attached to a 1.0-m rope and whirled in a vertical circle. The rope will break when the tension exceeds 450 N. What is the maximum speed the ball can have at the bottom of the circle without breaking the rope?
Answers
Answered by
bobpursley
max tension is at the bottom
tensionmax=mg+mv^2/r solve for v
tensionmax=mg+mv^2/r solve for v
Answered by
Sidrah Naeemuddin
T=mv^2/r + mg
or T= mg + mv^2/r
T= 450N r= 1
m= 0.75
450 = (o.75)(9.8) + (0.75)(v^2)
v^2= 450/8
v= 7.5
or T= mg + mv^2/r
T= 450N r= 1
m= 0.75
450 = (o.75)(9.8) + (0.75)(v^2)
v^2= 450/8
v= 7.5
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.