Question

A 0.50-kg ball is attached to a string of 0.50 m and swung in a horizontal circle with a velocity of 1.0 m/s. Find the centripetal force of the ball.

ac=1.0^2/0.5
=2
2(.50)
= 1.0 N

Answer 1

Correct.
a = V^2/R = 2 m/s^2 and
F = Ma = 1.0 N