Asked by jack
An astronaut on Neptune drops a rock straight downward from a height of 0.95 m. If the acceleration of gravity on Neptune is 11.2 m/s2, what is the speed of the rock just before it lands? (m/s)
Answers
Answered by
drwls
A dropped object attains a velocity of
V = sqrt(2 a X)
when falling a distance X.
Use the Neptune gravity acceleration value for a.
V = sqrt(2 a X)
when falling a distance X.
Use the Neptune gravity acceleration value for a.
Answered by
Anonymous
4.61
Answered by
Esther Frimpong
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