Asked by Erin

An Astronaut on the Moon drops a rock straight downward from a height of 1.25 meters. If the acceleration of gravity on the Moon is 1.62 meters per second squared, what is the speed of the rock just before it lands?
Answered by drwls
V = sqrt(2 a X) when the initial velocity is zero.

a is the acceleration rate
X is the distance fallen
Solve for V
Answered by Anonymous
345
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