Question

Identify all the zeros of the function y = 3 (x-2) (x+1) (x-4)

A
1
B
-1
C
2
D
-2
E
3
F
-3
G
4
H
-4

Answer 1

To find the zeros of the function \( y = 3 (x-2) (x+1) (x-4) \), we set the function equal to zero:

\[ 3 (x-2) (x+1) (x-4) = 0 \]

Since the product equals zero, we can set each factor to zero:

1. \( x - 2 = 0 \) → \( x = 2 \)
2. \( x + 1 = 0 \) → \( x = -1 \)
3. \( x - 4 = 0 \) → \( x = 4 \)

Thus, the zeros of the function are \( x = 2 \), \( x = -1 \), and \( x = 4 \).

From the given options, the identified zeros are:
- \( -1 \) (B)
- \( 2 \) (C)
- \( 4 \) (G)

So, the correct answers are:
**B, C, G**.