Question

Identify all the zeros of the function y= 3(x-2)(x+1)(x-4)

A
1
B
-1
C
2
D
-2
E
3
F
-3
G
4
H
-4

Answer 1

To identify the zeros of the function \( y = 3(x-2)(x+1)(x-4) \), we need to find the values of \( x \) for which \( y = 0 \).

Since the function is already factored, we can set each factor equal to zero:

1. \( x - 2 = 0 \) → \( x = 2 \)
2. \( x + 1 = 0 \) → \( x = -1 \)
3. \( x - 4 = 0 \) → \( x = 4 \)

Thus, the zeros of the function are:

- \( x = 2 \)
- \( x = -1 \)
- \( x = 4 \)

Now let's match these zeros with the choices given:

A. 1
B. -1 ✔
C. 2 ✔
D. -2
E. 3
F. -3
G. 4 ✔
H. -4

The zeros of the function are \( -1 \), \( 2 \), and \( 4 \).