Question

Identify all the zeros of the function y=3(x-2)(x+1)(x-4)

A
1
B
-1
C
2
D
-2
E
3
F
-3
G
4
H
-4

Answer 1

To find the zeros of the function \( y = 3(x-2)(x+1)(x-4) \), we set \( y \) equal to zero:

\[
3(x-2)(x+1)(x-4) = 0
\]

Since the constant factor 3 does not affect the zeros of the function, we can focus on the expression inside the parentheses:

\[
(x-2)(x+1)(x-4) = 0
\]

To find the zeros, we can set each factor equal to zero:

1. \( x - 2 = 0 \) → \( x = 2 \)
2. \( x + 1 = 0 \) → \( x = -1 \)
3. \( x - 4 = 0 \) → \( x = 4 \)

Therefore, the zeros of the function are:

- \( 2 \) (C)
- \( -1 \) (B)
- \( 4 \) (G)

The identified zeros from the provided options are:

- B: -1
- C: 2
- G: 4

The complete set of zeros of the function is \( x = 2, -1, \) and \( 4 \).