Question
Question 1
A)Calculate the volume of a sphere that has a radius of 7 cm using 3.14 for pi and round to the nearest hundredth.(1 point)
Responses
1,436.03 cm3
1,436.03 cm cubed
179.50 cm3
179.50 cm cubed
87.92 cm3
87.92 cm cubed
205.15 cm3
205.15 cm cubed
Question 2
A)Shakira is making a round piñata for a celebration. Her plan is to fill the inside with confetti. If the piñata measures 18 inches in diameter, what is its volume using 3.14 for pi and rounded to the nearest tenth?(1 point)
Responses
3,052.1 inches3
3,052.1 inches cubed
339.1 inches3
339.1 inches cubed
113.0 inches3
113.0 inches cubed
24,416.7 inches3
24,416.7 inches cubed
Question 3
A)
Use the image to answer the question.
A circle is traced along the circumference of a sphere at the center like a latitude. A dot is plotted at the center. The radius measures 5 feet.
What is the volume of the sphere using 3.14 for pi and rounded to the nearest tenth?
(1 point)
Responses
523.3 ft.3
523.3 ft. cubed
104.7 ft.3
104.7 ft. cubed
4,188.8 ft.3
4,188.8 ft. cubed
62.8 ft.3
62.8 ft. cubed
Question 4
A)You purchase a soccer ball that at full capacity measures 8 inches in diameter. How much air can the ball hold if it is pumped to full capacity? Calculate using 3.14 for pi and round to the nearest whole number.(1 point)
Responses
268 inches3
268 inches cubed
67 inches3
67 inches cubed
2,144 inches3
2,144 inches cubed
50 inches3
50 inches cubed
Question 5
A)
Use the image to answer the question.
A circle is traced along the circumference of a sphere at the center like a latitude. A dot is plotted at the center. The radius measures 3 centimeters.
Calculate the volume of the sphere using 3.14 for pi and round to the nearest tenth.
(1 point)
Responses
904.3 cm3
904.3 cm cubed
37.7 cm3
37.7 cm cubed
113.0 cm3
A)Calculate the volume of a sphere that has a radius of 7 cm using 3.14 for pi and round to the nearest hundredth.(1 point)
Responses
1,436.03 cm3
1,436.03 cm cubed
179.50 cm3
179.50 cm cubed
87.92 cm3
87.92 cm cubed
205.15 cm3
205.15 cm cubed
Question 2
A)Shakira is making a round piñata for a celebration. Her plan is to fill the inside with confetti. If the piñata measures 18 inches in diameter, what is its volume using 3.14 for pi and rounded to the nearest tenth?(1 point)
Responses
3,052.1 inches3
3,052.1 inches cubed
339.1 inches3
339.1 inches cubed
113.0 inches3
113.0 inches cubed
24,416.7 inches3
24,416.7 inches cubed
Question 3
A)
Use the image to answer the question.
A circle is traced along the circumference of a sphere at the center like a latitude. A dot is plotted at the center. The radius measures 5 feet.
What is the volume of the sphere using 3.14 for pi and rounded to the nearest tenth?
(1 point)
Responses
523.3 ft.3
523.3 ft. cubed
104.7 ft.3
104.7 ft. cubed
4,188.8 ft.3
4,188.8 ft. cubed
62.8 ft.3
62.8 ft. cubed
Question 4
A)You purchase a soccer ball that at full capacity measures 8 inches in diameter. How much air can the ball hold if it is pumped to full capacity? Calculate using 3.14 for pi and round to the nearest whole number.(1 point)
Responses
268 inches3
268 inches cubed
67 inches3
67 inches cubed
2,144 inches3
2,144 inches cubed
50 inches3
50 inches cubed
Question 5
A)
Use the image to answer the question.
A circle is traced along the circumference of a sphere at the center like a latitude. A dot is plotted at the center. The radius measures 3 centimeters.
Calculate the volume of the sphere using 3.14 for pi and round to the nearest tenth.
(1 point)
Responses
904.3 cm3
904.3 cm cubed
37.7 cm3
37.7 cm cubed
113.0 cm3
Answers
GPT-4o mini
To answer the questions, we'll use the formula for the volume of a sphere, which is:
\[
V = \frac{4}{3} \pi r^3
\]
where \( V \) is the volume, \( \pi \) is approximately 3.14, and \( r \) is the radius of the sphere.
### Question 1
**Given:** Radius = 7 cm
\[
V = \frac{4}{3} \times 3.14 \times (7)^3
\]
\[
V = \frac{4}{3} \times 3.14 \times 343
\]
\[
V = \frac{4}{3} \times 1077.32 \approx 1436.03 \text{ cm}^3
\]
**Answer:** 1,436.03 cm³
---
### Question 2
**Given:** Diameter = 18 inches, so radius \( r = \frac{18}{2} = 9 \) inches
\[
V = \frac{4}{3} \times 3.14 \times (9)^3
\]
\[
V = \frac{4}{3} \times 3.14 \times 729
\]
\[
V = \frac{4}{3} \times 2290.26 \approx 3052.1 \text{ in}^3
\]
**Answer:** 3,052.1 inches³
---
### Question 3
**Given:** Radius = 5 feet
\[
V = \frac{4}{3} \times 3.14 \times (5)^3
\]
\[
V = \frac{4}{3} \times 3.14 \times 125
\]
\[
V = \frac{4}{3} \times 392.5 \approx 523.3 \text{ ft}^3
\]
**Answer:** 523.3 ft³
---
### Question 4
**Given:** Diameter = 8 inches, so radius \( r = \frac{8}{2} = 4 \) inches
\[
V = \frac{4}{3} \times 3.14 \times (4)^3
\]
\[
V = \frac{4}{3} \times 3.14 \times 64
\]
\[
V = \frac{4}{3} \times 200.96 \approx 268 \text{ in}^3
\]
**Answer:** 268 inches³
---
### Question 5
**Given:** Radius = 3 cm
\[
V = \frac{4}{3} \times 3.14 \times (3)^3
\]
\[
V = \frac{4}{3} \times 3.14 \times 27
\]
\[
V = \frac{4}{3} \times 84.78 \approx 113.0 \text{ cm}^3
\]
**Answer:** 113.0 cm³
---
This should cover all the questions and their respective calculations!
\[
V = \frac{4}{3} \pi r^3
\]
where \( V \) is the volume, \( \pi \) is approximately 3.14, and \( r \) is the radius of the sphere.
### Question 1
**Given:** Radius = 7 cm
\[
V = \frac{4}{3} \times 3.14 \times (7)^3
\]
\[
V = \frac{4}{3} \times 3.14 \times 343
\]
\[
V = \frac{4}{3} \times 1077.32 \approx 1436.03 \text{ cm}^3
\]
**Answer:** 1,436.03 cm³
---
### Question 2
**Given:** Diameter = 18 inches, so radius \( r = \frac{18}{2} = 9 \) inches
\[
V = \frac{4}{3} \times 3.14 \times (9)^3
\]
\[
V = \frac{4}{3} \times 3.14 \times 729
\]
\[
V = \frac{4}{3} \times 2290.26 \approx 3052.1 \text{ in}^3
\]
**Answer:** 3,052.1 inches³
---
### Question 3
**Given:** Radius = 5 feet
\[
V = \frac{4}{3} \times 3.14 \times (5)^3
\]
\[
V = \frac{4}{3} \times 3.14 \times 125
\]
\[
V = \frac{4}{3} \times 392.5 \approx 523.3 \text{ ft}^3
\]
**Answer:** 523.3 ft³
---
### Question 4
**Given:** Diameter = 8 inches, so radius \( r = \frac{8}{2} = 4 \) inches
\[
V = \frac{4}{3} \times 3.14 \times (4)^3
\]
\[
V = \frac{4}{3} \times 3.14 \times 64
\]
\[
V = \frac{4}{3} \times 200.96 \approx 268 \text{ in}^3
\]
**Answer:** 268 inches³
---
### Question 5
**Given:** Radius = 3 cm
\[
V = \frac{4}{3} \times 3.14 \times (3)^3
\]
\[
V = \frac{4}{3} \times 3.14 \times 27
\]
\[
V = \frac{4}{3} \times 84.78 \approx 113.0 \text{ cm}^3
\]
**Answer:** 113.0 cm³
---
This should cover all the questions and their respective calculations!