To solve each of the equations for the center and radius of the circles by completing the square, we will go through them one by one.
Question 1:
Given equation: \[ x^2 + y^2 + 12x - 18y + 17 = 0 \]
Rearranging: \[ x^2 + 12x + y^2 - 18y + 17 = 0 \] \[ x^2 + 12x + y^2 - 18y = -17 \]
Completing the square:
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For \(x\): \[ x^2 + 12x \rightarrow (x + 6)^2 - 36 \]
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For \(y\): \[ y^2 - 18y \rightarrow (y - 9)^2 - 81 \]
Now substituting back: \[ (x + 6)^2 - 36 + (y - 9)^2 - 81 = -17 \] \[ (x + 6)^2 + (y - 9)^2 - 117 = -17 \] \[ (x + 6)^2 + (y - 9)^2 = 100 \]
Center and radius:
- Center: \((-6, 9)\)
- Radius: \(10\)
Correct Response:
- center=(−6,9), radius=10
Question 2:
Given equation: \[ x^2 + y^2 - 8x + 2y = 8 \]
Rearranging: \[ x^2 - 8x + y^2 + 2y = 8 \]
Completing the square:
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For \(x\): \[ x^2 - 8x \rightarrow (x - 4)^2 - 16 \]
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For \(y\): \[ y^2 + 2y \rightarrow (y + 1)^2 - 1 \]
Now substituting back: \[ (x - 4)^2 - 16 + (y + 1)^2 - 1 = 8 \] \[ (x - 4)^2 + (y + 1)^2 - 17 = 8 \] \[ (x - 4)^2 + (y + 1)^2 = 25 \]
Center and radius:
- Center: \((4, -1)\)
- Radius: \(5\)
Correct Response:
- center=(4,−1), radius=5
Question 3:
Given equation: \[ x^2 + y^2 - 2x + 22y + 1 = 0 \]
Rearranging: \[ x^2 - 2x + y^2 + 22y + 1 = 0 \]
Completing the square:
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For \(x\): \[ x^2 - 2x \rightarrow (x - 1)^2 - 1 \]
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For \(y\): \[ y^2 + 22y \rightarrow (y + 11)^2 - 121 \]
Now substituting back: \[ (x - 1)^2 - 1 + (y + 11)^2 - 121 + 1 = 0 \] \[ (x - 1)^2 + (y + 11)^2 - 121 = 0 \] \[ (x - 1)^2 + (y + 11)^2 = 121 \]
Center and radius:
- Center: \((1, -11)\)
- Radius: \(11\)
Correct Response:
- center=(1,−11), radius=11
Question 4:
Given equation: \[ x^2 + y^2 - 16x - 6y = -24 \]
Rearranging: \[ x^2 - 16x + y^2 - 6y = -24 \]
Completing the square:
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For \(x\): \[ x^2 - 16x \rightarrow (x - 8)^2 - 64 \]
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For \(y\): \[ y^2 - 6y \rightarrow (y - 3)^2 - 9 \]
Now substituting back: \[ (x - 8)^2 - 64 + (y - 3)^2 - 9 = -24 \] \[ (x - 8)^2 + (y - 3)^2 - 73 = -24 \] \[ (x - 8)^2 + (y - 3)^2 = 49 \]
Center and radius:
- Center: \((8, 3)\)
- Radius: \(7\)
Correct Response:
- center=(8,3), radius=7
Question 5:
Given equation: \[ x^2 + y^2 - 20x - 14y + 5 = 0 \]
Rearranging: \[ x^2 - 20x + y^2 - 14y + 5 = 0 \]
Completing the square:
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For \(x\): \[ x^2 - 20x \rightarrow (x - 10)^2 - 100 \]
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For \(y\): \[ y^2 - 14y \rightarrow (y - 7)^2 - 49 \]
Now substituting back: \[ (x - 10)^2 - 100 + (y - 7)^2 - 49 + 5 = 0 \] \[ (x - 10)^2 + (y - 7)^2 - 144 = 0 \] \[ (x - 10)^2 + (y - 7)^2 = 144 \]
Center and radius:
- Center: \((10, 7)\)
- Radius: \(12\)
Note: There might be a miscalculation here as none of the provided options correspond accurately to the findings.
None of the responses for question 5 are correct based on my calculations.
To summarize the correct results:
- Question 1: center=(-6,9), radius=10
- Question 2: center=(4,−1), radius=5
- Question 3: center=(1,−11), radius=11
- Question 4: center=(8,3), radius=7
- Question 5: No correct responses available based on calculations.