To solve the factored quadratic equation \((19x - 3)(9 + x) = 0\), we need to set each factor equal to zero.
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Set \(19x - 3 = 0\): \[ 19x = 3 \ x = \frac{3}{19} \]
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Set \(9 + x = 0\): \[ x = -9 \]
Now we have the solutions:
- \(x = \frac{3}{19}\)
- \(x = -9\)
The solution set, with the lesser number first, is: \[ { -9, \frac{3}{19} } \]