Solve the factored quadratic equation (19x−3)(9+x)=0

Question

. Enter the lesser number first. Use whole numbers or fractions for the answers.(2 points)
The solution set is {
,
}

Answer 1

To solve the factored quadratic equation \((19x - 3)(9 + x) = 0\), we set each factor equal to zero:

1. Setting the first factor equal to zero: \[ 19x - 3 = 0 \] \[ 19x = 3 \] \[ x = \frac{3}{19} \]

2. Setting the second factor equal to zero: \[ 9 + x = 0 \] \[ x = -9 \]

Now we have two solutions:

• \(x = \frac{3}{19}\)
• \(x = -9\)

The solution set, with the lesser number first, is: \[ { -9, \frac{3}{19} } \]