Solve the factored quadratic equation (19x−3)(9+x)=0

Question

. Enter the lesser number first.(2 points)
The solution set is {

Answer 1

To solve the factored quadratic equation \((19x - 3)(9 + x) = 0\), we can set each factor equal to zero.

1. Set the first factor to zero: \[ 19x - 3 = 0 \] \[ 19x = 3 \] \[ x = \frac{3}{19} \]

2. Set the second factor to zero: \[ 9 + x = 0 \] \[ x = -9 \]

Now we have the two solutions: \( x = \frac{3}{19} \) and \( x = -9 \).

Since the instructions specify to enter the lesser number first, we present the solution set as: \[ { -9, \frac{3}{19} } \]