3Ca(NO3)2(aq)+2Na3PO4(aq)->Ca3(PO4)2(s)+6NaNO3(aq)

A.)the moles Na3PO4 required to react with 2.03 L of 0.891 M Ca(NO3)2

B.)the grams of Ca3(PO4)2 that can be obtained from 136 mL of 0.627 M Ca(NO3)2

C.)the volume of 0.76 M Na3PO4 needed to react with 25 mL of 0.79 M Ca3(NO3)2

D.) the molarity (M) of the Ca(NO3)2 solution when 48.6 mL react with 52.8 mL of 4.1 M Na3PO4

2 answers

What is it that you are having trouble with.
the whole problem im not sure what i have to do that's the reason why i posted this question on this website so someone can help me.
Similar Questions
  1. 3Ca(NO3)2(aq)+2Na3PO4(aq)->Ca3(PO4)2(s)+6NaNO3(aq)(a) the grams of Ca3(PO4)2 that can be obtained from 126 mL of 0.750 M
    1. answers icon 0 answers
  2. 3CaCl2 + 2Na3PO4 → Ca3(PO4)2 + 6NaCl1. How many grams of Na³PO⁴ are needed to react with 4 moles of CaCl² ? 2. How
    1. answers icon 2 answers
  3. 2Na3PO4(aq)+3 Ba(NO3)2(aq)---->Ba3(PO4)2(s)+6NaNO3(aq)a solution containing 3.50g of Na3PO4 is mixed with a solution containing
    1. answers icon 1 answer
  4. Refer to 3CuCl2 (aq)+2Na3PO4 (aq) = Cu3(PO4)2+6NaCl (aq)If a student started with 18 grams of CuCl2 and enough Na3PO4 to
    1. answers icon 1 answer
more similar questions