Ask a New Question

3Ca(NO3)2(aq)+2Na3PO4(aq)->Ca3(PO4)2(s)+6NaNO3(aq)

(a) the grams of Ca3(PO4)2 that can be obtained from 126 mL of 0.750 M Ca(NO3)2

(b) the volume of 0.10 M Na3PO4 needed to react with 13 mL of 0.30 M Ca3(NO3)2

(c) the molarity (M) of the Ca(NO3)2 solution when 46.0 mL react with 57.3 mL of 3.8 M Na3PO4

Ask a New Question or answer this question.

Similar Questions

3Ca(NO3)2(aq)+2Na3PO4(aq)->Ca3(PO4)2(s)+6NaNO3(aq)A.)the moles Na3PO4 required to react with 2.03 L of 0.891 M Ca(NO3)2 B.)the
1. 2 answers
2Na3PO4(aq)+3 Ba(NO3)2(aq)---->Ba3(PO4)2(s)+6NaNO3(aq)a solution containing 3.50g of Na3PO4 is mixed with a solution containing
1. 1 answer
Using the balanced equation, determine the number of NaNO3 units in the visualization in the reaction.3Ca(NO3)2(aq) +
1. 1 answer
Identify the precipitate in this reaction: calcium nitrate reacts with sodium phosphate.2Na3PO4 + 3Ca(NO3)2--->6NaNO3 +
1. 2 answers

more similar questions