3CaCl2 + 2Na3PO4 → Ca3(PO4)2 + 6NaCl
1. How many grams of Na³PO⁴ are needed to react with 4 moles of CaCl² ?
Convert moles CaCl2 you have to moles Na3PO4 needed by using the coefficients in the balanced equation this way.
4 mols CaCl2 x (2 moles Na3PO4/3 moles CaCl2) = 4 x 2/3 = ?
Then grams Na3PO4 = moles Na3PO4 x molar mass Na3PO4.
2 and 3 are worked the same way. Post your work if you get stuck.
3CaCl2 + 2Na3PO4 → Ca3(PO4)2 + 6NaCl
1. How many grams of Na³PO⁴ are needed to react with 4 moles of CaCl² ?
2. How many grams of CaCl² are needed to react with 6 moles of Na³PO⁴ ?
3. How many grams of Ca³ (PO⁴)² will produce by 8 moles of Na³PO⁴?
2 answers
I still don't understand