Asked by Ana

how do i solve for y in the equation -5y(6y - 6) - y = -4(y - 5)
Answered by Reiny
-5y(6y - 6) - y = -4(y - 5)
-30y^2 + 30y - y = -4y + 20
30y^2 - 33y + 20 = 0
y = (22 ± √-1311)/60
or
(22 ± i √1311)/60 , two complex roots.
Answered by danny
how kan i solve this equation
7a-3a+2a-a=16
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