To find the length of \( PQ \) between the points \( P(-7, 6) \) and \( Q(5, -4) \), we can use the distance formula:
\[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \]
Where \( (x_1, y_1) \) are the coordinates of point \( P \) and \( (x_2, y_2) \) are the coordinates of point \( Q \).
Substituting the coordinates \( P(-7, 6) \) and \( Q(5, -4) \) into the formula, we have:
- \( x_1 = -7 \)
- \( y_1 = 6 \)
- \( x_2 = 5 \)
- \( y_2 = -4 \)
Now, calculate the differences:
\[ x_2 - x_1 = 5 - (-7) = 5 + 7 = 12 \]
\[ y_2 - y_1 = -4 - 6 = -10 \]
Now plug these values into the distance formula:
\[ d = \sqrt{(12)^2 + (-10)^2} \]
Calculating the squares:
\[ d = \sqrt{144 + 100} = \sqrt{244} \]
Now, we can simplify \( \sqrt{244} \):
\[ \sqrt{244} = \sqrt{4 \cdot 61} = 2\sqrt{61} \]
Next, we can approximate \( \sqrt{61} \):
\[ \sqrt{61} \approx 7.81 \quad (\text{since } 7.81^2 \approx 61) \]
Hence, we find:
\[ d \approx 2 \cdot 7.81 = 15.62 \]
Comparing this result to the given options:
- A: 14.4 units
- B: 14.8 units
- C: 15.2 units
- D: 15.6 units
The closest measurement to \( 15.62 \) is \( D: 15.6 \) units.
Thus, the correct answer is:
D: 15.6 units