Question

Solve the system of two equations using substitution.
y = 2 + 3x
4x - 3y = -16 (1 point)
(2, 8)
(-2, - 4)
(-2, 4)
(2, 10)

Answer 1

To solve the system of equations using substitution, we have the equations:

1. \( y = 2 + 3x \)
2. \( 4x - 3y = -16 \)

We can use the first equation to substitute \( y \) in the second equation.

Substituting \( y \) in the second equation:

\[
4x - 3(2 + 3x) = -16
\]

Now, simplify the equation:

\[
4x - 6 - 9x = -16
\]

Combine the \( x \) terms:

\[
-5x - 6 = -16
\]

Now, add 6 to both sides:

\[
-5x = -10
\]

Now, divide by -5:

\[
x = 2
\]

Now that we have the value of \( x \), we can substitute it back into the first equation to find \( y \):

\[
y = 2 + 3(2) = 2 + 6 = 8
\]

Thus, the solution to the system is \( (x, y) = (2, 8) \).

The answer is \( (2, 8) \).