solve following system of equations

y = 3x + 6
y = -13x - 4

1 answer

To solve the system of equations y = 3x + 6 and y = -13x - 4, we can set the right sides of the equations equal to each other:

3x + 6 = -13x - 4

Next, let's add 13x to both sides and subtract 6 from both sides to isolate the variable x:

3x + 13x + 6 - 6 = -13x + 13x - 4 - 6

16x = -10

Now, divide both sides by 16 to solve for x:

(16x) / 16 = (-10) / 16

x = -10/16

Simplifying the fraction gives:

x = -5/8

Now that we have the value of x, we can substitute it back into one of the original equations to solve for y. Let's use the first equation y = 3x + 6:

y = 3(-5/8) + 6

y = -15/8 + 48/8

y = 33/8

Therefore, the solution to the system of equations is x = -5/8 and y = 33/8.