Solve the system of liner equations -3x-4y=-23 and 3x-5y=5

Answer 1

To solve the system of linear equations, we can use either substitution or elimination method.

Let's use the substitution method:
Step 1: Solve one equation for one variable in terms of the other variable.
From the first equation, we can solve for x:
-3x - 4y = -23
-3x = -23 + 4y
x = (4y - 23)/-3

Step 2: Substitute this expression for x into the second equation.
3x - 5y = 5
3((4y - 23)/-3) - 5y = 5
(4y - 23) - 5y = 5
-23 -y = 5
- y = 5 + 23
- y = 28
y = -28

Step 3: Substitute the value of y back into the first equation to find x.
-3x - 4(-28) = -23
-3x + 112 = -23
-3x = -23 - 112
-3x = -135
x = -135/-3
x = 45

Therefore, the solution to the system of linear equations is x = 45 and y = -28.