Question
A stone is dropped from the top of a cliff. It hits the ground below after 3.10 s. How high is the cliff?
Answers
drwls
If H is the distance fallen in time t,
H = (g/2) t^2
Set t = 3.10 s and solve for H.
g is the acceleration of gravity, 9.8 m/s^2
H = (g/2) t^2
Set t = 3.10 s and solve for H.
g is the acceleration of gravity, 9.8 m/s^2
anonymous
3.10 x 9.8=30.38
30.38^2=922.9444
922.9444/9.8^2
922.9444/19.6= 47.0m
30.38^2=922.9444
922.9444/9.8^2
922.9444/19.6= 47.0m