Asked by Anonymous
A stone is dropped from the edge of a roof, and hits the ground with a velocity of −170 feet per second. Assume the acceleration due to gravity is -32 feet per second squared. How high (in feet) is the roof?
I have found s which is 16^2 but I do not know what formula to use.
I have found s which is 16^2 but I do not know what formula to use.
Answers
Answered by
Reiny
distance = -16t^2 + h
velocity = -32t
but we know that is -170
so -32t = -170
t = 85/16 seconds
so how far his it fallen in 85/16 seconds?
distance = 16(85/16)^2
= 7225/16 ft or
appr 451.56 ft
velocity = -32t
but we know that is -170
so -32t = -170
t = 85/16 seconds
so how far his it fallen in 85/16 seconds?
distance = 16(85/16)^2
= 7225/16 ft or
appr 451.56 ft
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