Asked by Aisha naabba
A stone is dropped from the top of a tall building and at the same time another stone is thrown vertically upward from the ground level with a velocity of 20m/s the stones meet exectity 2s after their release how tall is the building
Answers
Answered by
Steve
Since the height of the falling stone is the same as that of the projected stone after 2 seconds,
h-4.9t^2 = 20t-4.9t^2
h = 20t = 40
h-4.9t^2 = 20t-4.9t^2
h = 20t = 40
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