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Asked by sha

Using only the digits 0 an 1, how many different numbers consisting of 8 digits can be formed?
15 years ago

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Answered by Reiny
Can your leading digit be 0 ?

if so, then the number of cases = 2^8 = 256
if not, the the number of cases = 1*2^7 = 128

(looks like you are studying the binary number system)
15 years ago
Answered by sha
yeah its the first one. thank you!
15 years ago

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