Asked by Anonymous
Twice the sum of the digits of a positive, two-digit integer is 19 greater than the ones digit. Reversing the digits decreases the number by 18.
Answers
Answered by
Steve
If the number is ab, then we have
2(a+b) = b+19
10b+a = 10a+b - 18
Now solve for a and b, and you see that the number is 75
2(a+b) = b+19
10b+a = 10a+b - 18
Now solve for a and b, and you see that the number is 75
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