Asked by adeline
the sum of the digits of a three digit number is six. the ten digit is one less than the units digit and the number is twelve more than one hundred times the hundred digit
Find the three digits
x
y=x-1
z=7-2x
x+x-1+z=6
2x-1+z=6
z=7-2x
x-1=100(7-2x)+12
what is wrong with my reasoning?
Find the three digits
x
y=x-1
z=7-2x
x+x-1+z=6
2x-1+z=6
z=7-2x
x-1=100(7-2x)+12
what is wrong with my reasoning?
Answers
Answered by
Steve
It says "the number is twelve more than one hundred times the hundred digit"
The number is 100z+10y+x. So, you want
100z+10y+x = 100z+12
Now plug in your values and solve for x.
The number is 100z+10y+x. So, you want
100z+10y+x = 100z+12
Now plug in your values and solve for x.
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