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A 3.0 kg block being pulled across a table by a horizontal force of 80 N also experiences a frictional force of 5 N. What is the acceleration of the block?
15 years ago

Answers

drwls
a = F(net)/M = (80 - 5)/M
= 75/3 = 25 m/s^2
15 years ago
Bapps"three
f1= 80N ; f2=5N
F=f1 - f2 = 80N - 5N= 75N
F=M*a
a= F/M =75N/3kg =25 m/s^2

a=25 m/s^2
6 years ago

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