The net force pulling the block is
F = 16 - 3 = 13 N
The acceleration rate is
a = F/m = 6.5 m/s^2
The distance moved in thime t is
X = (a/2)*t^2
Substitute t = 5 s and compute.
A 2 kg block is pulled from rest along a horizontal surface by a rope with a force of 16 N. It experiences a constant frictional force of 3 N. How far has the block moved in the first five seconds?
1 answer
1 answer