a 15.5 kg block is pulled by two forces. The first is 11.8 N at a 53.7 angle and the second is 22.9 at a -15.8 angle. What is the magnitude of the acceleration

Answer 1

add the two forces to get the resultant force F. Then, as usual, |F| = m|a|

Answer 2

Given: F1 = 11.8N[53.7o],
F2 = 22.9N[-15.8o].
M = 15.5 kg.

Fr = 11.8(53.7o] + 22.9[-15.8],
Fr = (11.8*Cos53.7+22.9*Cos(-15.8)) + (11.8*sin53.7+22.9*sin(-15.8))I,
Fr = 29 + 3.2i,
Fr = sqrt(29^2+3.2^2) = Resultant force.

Fr = M*a.

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