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Two lines, a solid line and a dotted line, are drawn on a coordinate plane. Both the x-axis and y-axis range from negative 4 to 4 in 1-unit increments.
one line slants upward from -1, -3 to 1, 1 and another line goes horizontally from -3, 1 , which has a black dot, to -1, 1 which has an open white dot.
Create a piecewise function that represents the graph.

(1 point)
Responses

f(x)={1,2x−1,−3<x≤−1−1<x<1
f left parenthesis x right parenthesis equals left brace Start 2 by 2 Matrix 1st Row 1st Column 1 comma 2nd Column negative 3 less than x less-than-or-equal-to negative 1 2nd Row 1st Column 2 x minus 1 comma 2nd Column negative 1 less than x less than 1 End Matrix

f(x)={1,2x−1,−3≤x<−1−1≤x≤1
f left parenthesis x right parenthesis equals left brace Start 2 by 2 Matrix 1st Row 1st Column 1 comma 2nd Column negative 3 less-than-or-equal-to x less than negative 1 2nd Row 1st Column 2 x minus 1 comma 2nd Column negative 1 less-than-or-equal-to x less-than-or-equal-to 1 End Matrix

f(x)={x+1,2x−1, −3≤x<−1−1≤x≤1
f left parenthesis x right parenthesis equals left brace Start 2 by 2 Matrix 1st Row 1st Column x plus 1 comma 2nd Column negative 3 less-than-or-equal-to x less than negative 1 2nd Row 1st Column 2 x minus 1 comma 2nd Column negative 1 less-than-or-equal-to x less-than-or-equal-to 1 End Matrix

f(x)={1,2x, −3≤x<−1−1≤x≤1

label each answer with a number to make it easier on me.

Answer 1

Sure! Here are the responses labeled with numbers:

1. \( f(x) = \begin{cases}
1 & -3 < x \leq -1 \\
2x - 1 & -1 < x < 1
\end{cases} \)

2. \( f(x) = \begin{cases}
1 & -3 \leq x < -1 \\
2x - 1 & -1 \leq x \leq 1
\end{cases} \)

3. \( f(x) = \begin{cases}
x + 1 & -3 \leq x < -1 \\
2x - 1 & -1 \leq x \leq 1
\end{cases} \)

4. \( f(x) = \begin{cases}
1 & -3 \leq x < -1 \\
2x & -1 \leq x \leq 1
\end{cases} \)

Let me know if you need any further assistance!