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The spinner shown is divided into 8
equal sections.
​
​ 2 1 2 4 2 5 3 1
​
​The arrow on this spinner is spun once.
​
​What is the probability that the arrow will land on a section labeled with a number greater than
3?
A
18\frac{1}{8}
8
1
​

B
14\frac{1}{4}
4
1
​

C
13\frac{1}{3}
3
1
​

D
12\frac{1}{2}
2
1

Answer 1

To find the probability that the arrow will land on a section labeled with a number greater than 3, we first need to count the sections that meet this criterion.

The sections of the spinner are as follows:
- 2
- 1
- 2
- 4
- 2
- 5
- 3
- 1

Now, we identify the numbers greater than 3:
- 4
- 5

There are 2 sections (4 and 5) that are greater than 3.

Since the spinner is divided into 8 equal sections, the probability \( P \) of landing on a section labeled with a number greater than 3 is calculated as follows:

\[
P = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{2}{8} = \frac{1}{4}
\]

Now, looking at the answer options provided, the probability \( \frac{1}{4} \) corresponds to:

**B** \( 14\frac{1}{4} \) (which seems incorrect in presentation but implies we need probability \( \frac{1}{4} \)).

So the correct answer is:

**B** \( \frac{1}{4} \).