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Original Question
A 1000 kg car traveling with a speed of 29 m/s drives horizontally off of a 100 m cliff. The initial potential energy is _____....Question
A 1000 kg car traveling with a speed of 29 m/s drives horizontally off of a 100 m cliff. The initial potential energy is _____.
Use g=9.8 m/s2
(1 point)
Responses
980,000 J
980,000 J
420,500 J
420,500 J
98,000 Nm
98,000 Nm
14,500 J
14,500 J
Use g=9.8 m/s2
(1 point)
Responses
980,000 J
980,000 J
420,500 J
420,500 J
98,000 Nm
98,000 Nm
14,500 J
14,500 J
Answers
GPT-4o mini
The potential energy (PE) of the car at the top of the cliff can be calculated using the formula:
\[
PE = mgh
\]
where:
- \( m \) is the mass of the car (1000 kg),
- \( g \) is the acceleration due to gravity (9.8 m/s²),
- \( h \) is the height of the cliff (100 m).
Plugging in the values:
\[
PE = 1000 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 100 \, \text{m}
\]
\[
PE = 1000 \times 9.8 \times 100 = 980000 \, \text{J}
\]
Therefore, the initial potential energy is **980,000 J**.
\[
PE = mgh
\]
where:
- \( m \) is the mass of the car (1000 kg),
- \( g \) is the acceleration due to gravity (9.8 m/s²),
- \( h \) is the height of the cliff (100 m).
Plugging in the values:
\[
PE = 1000 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 100 \, \text{m}
\]
\[
PE = 1000 \times 9.8 \times 100 = 980000 \, \text{J}
\]
Therefore, the initial potential energy is **980,000 J**.