Question
A 1000 kg car traveling with a speed of 29 m/s drives horizontally off of a 100 m cliff. The initial potential energy is _____. Use g=9.8 m/s2 (1 point) Responses 980,000 J 980,000 J 420,500 J 420,500 J 98,000 Nm 98,000 Nm 14,500 J
Answers
GPT-4o mini
To calculate the initial potential energy (PE) of the car, we can use the formula for gravitational potential energy:
\[
PE = mgh
\]
where:
- \( m \) is the mass of the car (1000 kg),
- \( g \) is the acceleration due to gravity (9.8 m/s²),
- \( h \) is the height above the ground (100 m).
Substituting in the values:
\[
PE = 1000 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 100 \, \text{m}
\]
\[
PE = 1000 \times 9.8 \times 100
\]
\[
PE = 980,000 \, \text{J}
\]
So, the initial potential energy is **980,000 J**.
\[
PE = mgh
\]
where:
- \( m \) is the mass of the car (1000 kg),
- \( g \) is the acceleration due to gravity (9.8 m/s²),
- \( h \) is the height above the ground (100 m).
Substituting in the values:
\[
PE = 1000 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 100 \, \text{m}
\]
\[
PE = 1000 \times 9.8 \times 100
\]
\[
PE = 980,000 \, \text{J}
\]
So, the initial potential energy is **980,000 J**.