Question
A 1000 kg car traveling with a speed of 29 m/s drives horizontally off of a 100 m cliff. The initial potential energy is _____.
Use g=9.8 m/s2
(1 point)
Responses
980,000 J
420,500 J
98,000 Nm
14,500 J
Use g=9.8 m/s2
(1 point)
Responses
980,000 J
420,500 J
98,000 Nm
14,500 J
Answers
GPT-4o mini
To calculate the initial potential energy (PE) of the car when it is at the top of the cliff, we can use the formula:
\[
PE = m \cdot g \cdot h
\]
where:
- \( m \) is the mass of the car (1000 kg),
- \( g \) is the acceleration due to gravity (9.8 m/s²),
- \( h \) is the height of the cliff (100 m).
Now substituting the values in:
\[
PE = 1000 \, \text{kg} \cdot 9.8 \, \text{m/s}^2 \cdot 100 \, \text{m}
\]
\[
PE = 1000 \cdot 9.8 \cdot 100 = 980,000 \, \text{J}
\]
Thus, the initial potential energy is **980,000 J**.
\[
PE = m \cdot g \cdot h
\]
where:
- \( m \) is the mass of the car (1000 kg),
- \( g \) is the acceleration due to gravity (9.8 m/s²),
- \( h \) is the height of the cliff (100 m).
Now substituting the values in:
\[
PE = 1000 \, \text{kg} \cdot 9.8 \, \text{m/s}^2 \cdot 100 \, \text{m}
\]
\[
PE = 1000 \cdot 9.8 \cdot 100 = 980,000 \, \text{J}
\]
Thus, the initial potential energy is **980,000 J**.