Asked by hudson
Find the inverse relation of f(x)=(5x−2)8
algebraically by letting y=x
.(1 point)
Responses
y=(5x+2)8
y equals Start Fraction left parenthesis 5 x plus 2 right parenthesis over 8 End Fraction
y=(8x−2)5
y equals Start Fraction left parenthesis 8 x minus 2 right parenthesis over 5 End Fraction
y=85(x+2)
y equals Start Fraction 8 over 5 End Fraction left parenthesis x plus 2 right parenthesis
y=15(8x+2)
algebraically by letting y=x
.(1 point)
Responses
y=(5x+2)8
y equals Start Fraction left parenthesis 5 x plus 2 right parenthesis over 8 End Fraction
y=(8x−2)5
y equals Start Fraction left parenthesis 8 x minus 2 right parenthesis over 5 End Fraction
y=85(x+2)
y equals Start Fraction 8 over 5 End Fraction left parenthesis x plus 2 right parenthesis
y=15(8x+2)
Answers
Answered by
GPT-4o mini
To find the inverse relation of \( f(x) = (5x - 2)8 \) algebraically, we start by letting \( y = f(x) \):
\[
y = (5x - 2)8
\]
Next, we will solve for \( x \) in terms of \( y \):
1. Divide both sides by 8:
\[
\frac{y}{8} = 5x - 2
\]
2. Add 2 to both sides:
\[
\frac{y}{8} + 2 = 5x
\]
3. Divide both sides by 5 to solve for \( x \):
\[
x = \frac{\frac{y}{8} + 2}{5}
\]
Now we can simplify this expression:
\[
x = \frac{y + 16}{40}
\]
To express the inverse function, we swap \( x \) and \( y \):
\[
y = \frac{x + 16}{40}
\]
So the inverse function is:
\[
f^{-1}(x) = \frac{x + 16}{40}
\]
However, none of the provided responses match this calculation directly. Based on your initial function, it seems there may have been a misunderstanding or a need to re-check the problem setup or the function.
If \( f(x) = 8(5x - 2) \), the correct inverse would be found as shown. Otherwise, please clarify the setup for more precision.
\[
y = (5x - 2)8
\]
Next, we will solve for \( x \) in terms of \( y \):
1. Divide both sides by 8:
\[
\frac{y}{8} = 5x - 2
\]
2. Add 2 to both sides:
\[
\frac{y}{8} + 2 = 5x
\]
3. Divide both sides by 5 to solve for \( x \):
\[
x = \frac{\frac{y}{8} + 2}{5}
\]
Now we can simplify this expression:
\[
x = \frac{y + 16}{40}
\]
To express the inverse function, we swap \( x \) and \( y \):
\[
y = \frac{x + 16}{40}
\]
So the inverse function is:
\[
f^{-1}(x) = \frac{x + 16}{40}
\]
However, none of the provided responses match this calculation directly. Based on your initial function, it seems there may have been a misunderstanding or a need to re-check the problem setup or the function.
If \( f(x) = 8(5x - 2) \), the correct inverse would be found as shown. Otherwise, please clarify the setup for more precision.