The cost of one burger and one order of fries together is $6.30. The cost of two burgers and one order of fries is $10.60. What is the cost of one order of fries alone?(1 point)

Responses

$2.15
2 point 1 5 dollars

$4.30
4 point 3 0 dollars

$2.00
2 point 0 0 dollars

$3.53

1 answer

Let's use algebra to solve the problem.

Let \( b \) be the cost of one burger and \( f \) be the cost of one order of fries.

We have the following two equations based on the information provided:

  1. \( b + f = 6.30 \) (Equation 1)
  2. \( 2b + f = 10.60 \) (Equation 2)

Now, we can solve these equations step by step.

From Equation 1, we can express \( f \) in terms of \( b \):

\[ f = 6.30 - b \]

Now, we will substitute \( f \) into Equation 2:

\[ 2b + (6.30 - b) = 10.60 \]

Simplifying this equation:

\[ 2b + 6.30 - b = 10.60 \] \[ b + 6.30 = 10.60 \] \[ b = 10.60 - 6.30 \] \[ b = 4.30 \]

Now that we have \( b \), we can substitute back to find \( f \):

Using Equation 1:

\[ f = 6.30 - b \] \[ f = 6.30 - 4.30 \] \[ f = 2.00 \]

Therefore, the cost of one order of fries alone is $2.00.

So the answer is:

$2.00