Let's use algebra to solve the problem.
Let \( b \) be the cost of one burger and \( f \) be the cost of one order of fries.
We have the following two equations based on the information provided:
- \( b + f = 6.30 \) (Equation 1)
- \( 2b + f = 10.60 \) (Equation 2)
Now, we can solve these equations step by step.
From Equation 1, we can express \( f \) in terms of \( b \):
\[ f = 6.30 - b \]
Now, we will substitute \( f \) into Equation 2:
\[ 2b + (6.30 - b) = 10.60 \]
Simplifying this equation:
\[ 2b + 6.30 - b = 10.60 \] \[ b + 6.30 = 10.60 \] \[ b = 10.60 - 6.30 \] \[ b = 4.30 \]
Now that we have \( b \), we can substitute back to find \( f \):
Using Equation 1:
\[ f = 6.30 - b \] \[ f = 6.30 - 4.30 \] \[ f = 2.00 \]
Therefore, the cost of one order of fries alone is $2.00.
So the answer is:
$2.00