Let's define the variables:
- Let \( b \) be the cost of one burger.
- Let \( f \) be the cost of one order of fries.
From the problem statement, we have the following equations:
- \( b + f = 6.30 \) (Equation 1)
- \( 2b + f = 10.60 \) (Equation 2)
Now, we'll solve these equations.
From Equation 1, we can express \( f \) in terms of \( b \):
\[ f = 6.30 - b \]
Now substituting this expression for \( f \) into Equation 2:
\[ 2b + (6.30 - b) = 10.60 \]
Simplifying this:
\[ 2b + 6.30 - b = 10.60 \] \[ b + 6.30 = 10.60 \] \[ b = 10.60 - 6.30 \] \[ b = 4.30 \]
Now that we have the cost of one burger, we can find the cost of one order of fries using Equation 1:
\[ f = 6.30 - b = 6.30 - 4.30 = 2.00 \]
So, the cost of one order of fries alone is \( \boxed{2.00} \).