Question
The cost of one burger and one order of fries together is $6.30. The cost of two burgers and one order of fries is $10.60. What is the cost of one order of fries alone?(1 point)
Responses
$2.15
2 point 1 5 dollars
$2.00
2 point 0 0 dollars
$3.53
3 point 5 3 dollars
$4.30
Responses
$2.15
2 point 1 5 dollars
$2.00
2 point 0 0 dollars
$3.53
3 point 5 3 dollars
$4.30
Answers
Answered by
GPT-4o mini
Let's define the variables:
- Let \( b \) be the cost of one burger.
- Let \( f \) be the cost of one order of fries.
From the problem statement, we have the following equations:
1. \( b + f = 6.30 \) (Equation 1)
2. \( 2b + f = 10.60 \) (Equation 2)
Now, we'll solve these equations.
From Equation 1, we can express \( f \) in terms of \( b \):
\[
f = 6.30 - b
\]
Now substituting this expression for \( f \) into Equation 2:
\[
2b + (6.30 - b) = 10.60
\]
Simplifying this:
\[
2b + 6.30 - b = 10.60
\]
\[
b + 6.30 = 10.60
\]
\[
b = 10.60 - 6.30
\]
\[
b = 4.30
\]
Now that we have the cost of one burger, we can find the cost of one order of fries using Equation 1:
\[
f = 6.30 - b = 6.30 - 4.30 = 2.00
\]
So, the cost of one order of fries alone is \( \boxed{2.00} \).
- Let \( b \) be the cost of one burger.
- Let \( f \) be the cost of one order of fries.
From the problem statement, we have the following equations:
1. \( b + f = 6.30 \) (Equation 1)
2. \( 2b + f = 10.60 \) (Equation 2)
Now, we'll solve these equations.
From Equation 1, we can express \( f \) in terms of \( b \):
\[
f = 6.30 - b
\]
Now substituting this expression for \( f \) into Equation 2:
\[
2b + (6.30 - b) = 10.60
\]
Simplifying this:
\[
2b + 6.30 - b = 10.60
\]
\[
b + 6.30 = 10.60
\]
\[
b = 10.60 - 6.30
\]
\[
b = 4.30
\]
Now that we have the cost of one burger, we can find the cost of one order of fries using Equation 1:
\[
f = 6.30 - b = 6.30 - 4.30 = 2.00
\]
So, the cost of one order of fries alone is \( \boxed{2.00} \).
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