Let's define the variables:
- Let \( b \) = cost of one burger
- Let \( f \) = cost of one order of fries
From the problem, we have the following two equations:
- \( b + f = 6.30 \) (Equation 1)
- \( 2b + f = 10.60 \) (Equation 2)
Now, we can solve these equations step by step.
Step 1: Solve Equation 1 for \( f \)
From Equation 1: \[ f = 6.30 - b \]
Step 2: Substitute \( f \) into Equation 2
Now we substitute \( f \) in Equation 2: \[ 2b + (6.30 - b) = 10.60 \]
This simplifies to: \[ 2b + 6.30 - b = 10.60 \]
Combining like terms: \[ b + 6.30 = 10.60 \]
Step 3: Solve for \( b \)
Subtract 6.30 from both sides: \[ b = 10.60 - 6.30 \] \[ b = 4.30 \]
Step 4: Substitute \( b \) back to find \( f \)
Now, substitute \( b = 4.30 \) back into Equation 1 to find \( f \): \[ f = 6.30 - 4.30 \] \[ f = 2.00 \]
Therefore, the cost of one order of fries alone is $2.00.