Question
The cost of a large cheese pizza at a local pizzeria can be modeled with the function C(n)=16.5+2.5n
, where n is the number of toppings that can be added on. If a customer has $35 to spend, what is the maximum number of toppings that they can add to their large cheese pizza?(1 point)
With $35 to spend, they can add a maximum of
toppings to the pizza.
, where n is the number of toppings that can be added on. If a customer has $35 to spend, what is the maximum number of toppings that they can add to their large cheese pizza?(1 point)
With $35 to spend, they can add a maximum of
toppings to the pizza.
Answers
GPT-4o mini
To determine the maximum number of toppings that can be added to a large cheese pizza given a budget of $35, we can set up an inequality using the cost function \( C(n) = 16.5 + 2.5n \).
1. We want the total cost \( C(n) \) to be less than or equal to $35:
\[
C(n) \leq 35
\]
2. Plug in the cost function:
\[
16.5 + 2.5n \leq 35
\]
3. Subtract 16.5 from both sides:
\[
2.5n \leq 35 - 16.5
\]
\[
2.5n \leq 18.5
\]
4. Divide both sides by 2.5:
\[
n \leq \frac{18.5}{2.5}
\]
\[
n \leq 7.4
\]
Since \( n \) must be a whole number (you can't add a fraction of a topping), we take the largest whole number less than or equal to 7.4, which is 7.
Therefore, with $35 to spend, they can add a maximum of **7** toppings to the pizza.
1. We want the total cost \( C(n) \) to be less than or equal to $35:
\[
C(n) \leq 35
\]
2. Plug in the cost function:
\[
16.5 + 2.5n \leq 35
\]
3. Subtract 16.5 from both sides:
\[
2.5n \leq 35 - 16.5
\]
\[
2.5n \leq 18.5
\]
4. Divide both sides by 2.5:
\[
n \leq \frac{18.5}{2.5}
\]
\[
n \leq 7.4
\]
Since \( n \) must be a whole number (you can't add a fraction of a topping), we take the largest whole number less than or equal to 7.4, which is 7.
Therefore, with $35 to spend, they can add a maximum of **7** toppings to the pizza.