Question
Quiz
Question 1 (1 point)
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Aiden has a collection of 63 nickels and quarters in his piggy bank. If the total value of the coins is $10.75. How many nickels does he have? How many quarters does he have?
Question 1 options:
20 nickels and 43 quarters
25 nickels and 38 quarters
18 nickels and 45 quarters
38 nickels and 25 quarters
Question 2 (1 point)
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The sum of two numbers is 25. One number is twice the second number plus 7. What are the two numbers?
Question 2 options:
18 and 7
15 and 10
19 and 6
20 and 5
Question 3 (1 point)
Listen
Dustin has only nickels and quarters in his piggy bank. He has 49 coins total for a combined value of $8.85. How many of each coin does he have?
Question 3 options:
16 nickels and 33 quarters
32 nickels and 17 quarters
17 nickels and 32 quarters
25 nickels and 24 quarters
Question 4 (1 point)
Listen
Max has a collection of 99 dimes and pennies worth $4.41. How many of each coin does he have.
Question 4 options:
40 dimes and 59 pennies
34 dimes and 65 pennies
61 dimes and 38 pennies
38 dimes and 61 pennies
Question 5 (1 point)
Listen
The sum of the two numbers in 53. Their difference is 25. Find both numbers.
Question 5 options:
16 and 37
30 and 23
42 and 11
39 and 14
0 of 5 questions saved
Listen
Question 1 (1 point)
Listen
Aiden has a collection of 63 nickels and quarters in his piggy bank. If the total value of the coins is $10.75. How many nickels does he have? How many quarters does he have?
Question 1 options:
20 nickels and 43 quarters
25 nickels and 38 quarters
18 nickels and 45 quarters
38 nickels and 25 quarters
Question 2 (1 point)
Listen
The sum of two numbers is 25. One number is twice the second number plus 7. What are the two numbers?
Question 2 options:
18 and 7
15 and 10
19 and 6
20 and 5
Question 3 (1 point)
Listen
Dustin has only nickels and quarters in his piggy bank. He has 49 coins total for a combined value of $8.85. How many of each coin does he have?
Question 3 options:
16 nickels and 33 quarters
32 nickels and 17 quarters
17 nickels and 32 quarters
25 nickels and 24 quarters
Question 4 (1 point)
Listen
Max has a collection of 99 dimes and pennies worth $4.41. How many of each coin does he have.
Question 4 options:
40 dimes and 59 pennies
34 dimes and 65 pennies
61 dimes and 38 pennies
38 dimes and 61 pennies
Question 5 (1 point)
Listen
The sum of the two numbers in 53. Their difference is 25. Find both numbers.
Question 5 options:
16 and 37
30 and 23
42 and 11
39 and 14
0 of 5 questions saved
Listen
Answers
Answered by
GPT-4o mini
Let's solve each of the questions one by one.
### Question 1:
Aiden has a collection of 63 nickels and quarters and their total value is $10.75.
Let:
- \( n \) be the number of nickels
- \( q \) be the number of quarters
We have the following equations:
1. \( n + q = 63 \) (total number of coins)
2. \( 0.05n + 0.25q = 10.75 \) (total value of coins in dollars)
To simplify the second equation, we can multiply everything by 100 to eliminate decimals:
\[
5n + 25q = 1075
\]
Now we have the system of equations:
1. \( n + q = 63 \)
2. \( 5n + 25q = 1075 \)
From equation (1), we can express \( n \) as \( n = 63 - q \).
Substituting into equation (2):
\[
5(63 - q) + 25q = 1075
\]
\[
315 - 5q + 25q = 1075
\]
\[
20q = 1075 - 315
\]
\[
20q = 760
\]
\[
q = 38
\]
Substituting \( q \) back to find \( n \):
\[
n = 63 - 38 = 25
\]
So, Aiden has **25 nickels and 38 quarters**.
### Question 2:
The sum of two numbers is 25. One number is twice the second number plus 7.
Let:
- \( x \) be the first number
- \( y \) be the second number
We have the equations:
1. \( x + y = 25 \)
2. \( x = 2y + 7 \)
Substituting equation (2) into (1):
\[
2y + 7 + y = 25
\]
\[
3y + 7 = 25
\]
\[
3y = 18
\]
\[
y = 6
\]
Substituting \( y \) back into (1):
\[
x + 6 = 25
\]
\[
x = 19
\]
The two numbers are **19 and 6**.
### Question 3:
Dustin has 49 coins total for a combined value of $8.85.
Let:
- \( n \) be the number of nickels
- \( q \) be the number of quarters
We have the equations:
1. \( n + q = 49 \)
2. \( 0.05n + 0.25q = 8.85 \)
Multiplying the second equation by 100:
\[
5n + 25q = 885
\]
Substituting \( n = 49 - q \) into the second equation:
\[
5(49 - q) + 25q = 885
\]
\[
245 - 5q + 25q = 885
\]
\[
20q = 885 - 245
\]
\[
20q = 640
\]
\[
q = 32
\]
Now substituting \( q \) back to find \( n \):
\[
n = 49 - 32 = 17
\]
Dustin has **17 nickels and 32 quarters**.
### Question 4:
Max has 99 dimes and pennies worth $4.41.
Let:
- \( d \) be the number of dimes
- \( p \) be the number of pennies
We have:
1. \( d + p = 99 \)
2. \( 0.10d + 0.01p = 4.41 \)
Multiplying the second equation by 100:
\[
10d + p = 441
\]
Now substituting \( p = 99 - d \) into the second equation:
\[
10d + (99 - d) = 441
\]
\[
10d + 99 - d = 441
\]
\[
9d + 99 = 441
\]
\[
9d = 342
\]
\[
d = 38
\]
Substituting \( d \) back to find \( p \):
\[
p = 99 - 38 = 61
\]
Max has **38 dimes and 61 pennies**.
### Question 5:
The sum of the two numbers is 53. Their difference is 25.
Let the two numbers be \( x \) and \( y \).
We have:
1. \( x + y = 53 \)
2. \( x - y = 25 \)
Adding the two equations together:
\[
(x + y) + (x - y) = 53 + 25
\]
\[
2x = 78
\]
\[
x = 39
\]
Now substituting \( x \) back to find \( y \):
\[
39 + y = 53
\]
\[
y = 14
\]
The two numbers are **39 and 14**.
### Summary of Answers:
1. **25 nickels and 38 quarters**
2. **19 and 6**
3. **17 nickels and 32 quarters**
4. **38 dimes and 61 pennies**
5. **39 and 14**
### Question 1:
Aiden has a collection of 63 nickels and quarters and their total value is $10.75.
Let:
- \( n \) be the number of nickels
- \( q \) be the number of quarters
We have the following equations:
1. \( n + q = 63 \) (total number of coins)
2. \( 0.05n + 0.25q = 10.75 \) (total value of coins in dollars)
To simplify the second equation, we can multiply everything by 100 to eliminate decimals:
\[
5n + 25q = 1075
\]
Now we have the system of equations:
1. \( n + q = 63 \)
2. \( 5n + 25q = 1075 \)
From equation (1), we can express \( n \) as \( n = 63 - q \).
Substituting into equation (2):
\[
5(63 - q) + 25q = 1075
\]
\[
315 - 5q + 25q = 1075
\]
\[
20q = 1075 - 315
\]
\[
20q = 760
\]
\[
q = 38
\]
Substituting \( q \) back to find \( n \):
\[
n = 63 - 38 = 25
\]
So, Aiden has **25 nickels and 38 quarters**.
### Question 2:
The sum of two numbers is 25. One number is twice the second number plus 7.
Let:
- \( x \) be the first number
- \( y \) be the second number
We have the equations:
1. \( x + y = 25 \)
2. \( x = 2y + 7 \)
Substituting equation (2) into (1):
\[
2y + 7 + y = 25
\]
\[
3y + 7 = 25
\]
\[
3y = 18
\]
\[
y = 6
\]
Substituting \( y \) back into (1):
\[
x + 6 = 25
\]
\[
x = 19
\]
The two numbers are **19 and 6**.
### Question 3:
Dustin has 49 coins total for a combined value of $8.85.
Let:
- \( n \) be the number of nickels
- \( q \) be the number of quarters
We have the equations:
1. \( n + q = 49 \)
2. \( 0.05n + 0.25q = 8.85 \)
Multiplying the second equation by 100:
\[
5n + 25q = 885
\]
Substituting \( n = 49 - q \) into the second equation:
\[
5(49 - q) + 25q = 885
\]
\[
245 - 5q + 25q = 885
\]
\[
20q = 885 - 245
\]
\[
20q = 640
\]
\[
q = 32
\]
Now substituting \( q \) back to find \( n \):
\[
n = 49 - 32 = 17
\]
Dustin has **17 nickels and 32 quarters**.
### Question 4:
Max has 99 dimes and pennies worth $4.41.
Let:
- \( d \) be the number of dimes
- \( p \) be the number of pennies
We have:
1. \( d + p = 99 \)
2. \( 0.10d + 0.01p = 4.41 \)
Multiplying the second equation by 100:
\[
10d + p = 441
\]
Now substituting \( p = 99 - d \) into the second equation:
\[
10d + (99 - d) = 441
\]
\[
10d + 99 - d = 441
\]
\[
9d + 99 = 441
\]
\[
9d = 342
\]
\[
d = 38
\]
Substituting \( d \) back to find \( p \):
\[
p = 99 - 38 = 61
\]
Max has **38 dimes and 61 pennies**.
### Question 5:
The sum of the two numbers is 53. Their difference is 25.
Let the two numbers be \( x \) and \( y \).
We have:
1. \( x + y = 53 \)
2. \( x - y = 25 \)
Adding the two equations together:
\[
(x + y) + (x - y) = 53 + 25
\]
\[
2x = 78
\]
\[
x = 39
\]
Now substituting \( x \) back to find \( y \):
\[
39 + y = 53
\]
\[
y = 14
\]
The two numbers are **39 and 14**.
### Summary of Answers:
1. **25 nickels and 38 quarters**
2. **19 and 6**
3. **17 nickels and 32 quarters**
4. **38 dimes and 61 pennies**
5. **39 and 14**
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