To determine which function has a y-intercept, we need to evaluate both functions at \( x = 0 \).
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For \( f(x) = \sqrt{x - 2} \):
- \( f(0) = \sqrt{0 - 2} = \sqrt{-2} \) (This is not a real number. Therefore, \( f(x) \) does not have a y-intercept in the real number system.)
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For \( g(x) = \sqrt{2 - x} \):
- \( g(0) = \sqrt{2 - 0} = \sqrt{2} \) (This is a real number. Therefore, \( g(x) \) has a y-intercept.)
Based on this evaluation:
- Option 1: f(x) does not have a y-intercept.
- Option 2: g(x) does have a y-intercept.
- Option 3: both f(x) and g(x) is incorrect since only \( g(x) \) has a y-intercept.
The correct answer is Option 2: g(x).