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Graph the square root functions f(x)=x−2−−−−√ and g(x)=2−x−−−−√ . Which function has a y -intercept? Enter the correct option n...Asked by hudson
Graph the square root functions f(x)=x−2−−−−√
and g(x)=2−x−−−−√
. Which function has a y
-intercept? Enter the correct option number.
Option 1: f(x)
Option 2: g(x)
Option 3: bothf(x)
and g(x)
(1 point)
and g(x)=2−x−−−−√
. Which function has a y
-intercept? Enter the correct option number.
Option 1: f(x)
Option 2: g(x)
Option 3: bothf(x)
and g(x)
(1 point)
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To determine which function has a y-intercept, we need to evaluate both functions at \( x = 0 \).
1. For \( f(x) = \sqrt{x - 2} \):
- \( f(0) = \sqrt{0 - 2} = \sqrt{-2} \) (This is not a real number. Therefore, \( f(x) \) does not have a y-intercept in the real number system.)
2. For \( g(x) = \sqrt{2 - x} \):
- \( g(0) = \sqrt{2 - 0} = \sqrt{2} \) (This is a real number. Therefore, \( g(x) \) has a y-intercept.)
Based on this evaluation:
- **Option 1: f(x)** does not have a y-intercept.
- **Option 2: g(x)** does have a y-intercept.
- **Option 3: both f(x) and g(x)** is incorrect since only \( g(x) \) has a y-intercept.
The correct answer is **Option 2: g(x)**.
1. For \( f(x) = \sqrt{x - 2} \):
- \( f(0) = \sqrt{0 - 2} = \sqrt{-2} \) (This is not a real number. Therefore, \( f(x) \) does not have a y-intercept in the real number system.)
2. For \( g(x) = \sqrt{2 - x} \):
- \( g(0) = \sqrt{2 - 0} = \sqrt{2} \) (This is a real number. Therefore, \( g(x) \) has a y-intercept.)
Based on this evaluation:
- **Option 1: f(x)** does not have a y-intercept.
- **Option 2: g(x)** does have a y-intercept.
- **Option 3: both f(x) and g(x)** is incorrect since only \( g(x) \) has a y-intercept.
The correct answer is **Option 2: g(x)**.
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