no,
logx 14 - logx 2
= logx (14/2)
- logx 7
Is this correct?
Express as a single logarithm.
log[x](14)-log[x](2)
Answer= log[x](12)
1 answer
Express as a single logarithm.
log[x](14)-log[x](2)
Answer= log[x](12)
1 answer